有没有办法在多个列表中找到公共元素？

def find_common_elements_brute_force(lists):
    if not lists:
        return []
    common_elements = lists[0]
    for lst in lists[1:]:
        common_elements = [elem for elem in common_elements if elem in lst]
    return common_elements

# 示例
lists = [[1, 2, 3], [2, 3, 4], [3, 4, 5]]
print(find_common_elements_brute_force(lists))  # 输出: [3]

def find_common_elements_set(lists):
    if not lists:
        return []
    sets = [set(lst) for lst in lists]
    common_elements = set.intersection(*sets)
    return list(common_elements)

# 示例
lists = [[1, 2, 3], [2, 3, 4], [3, 4, 5]]
print(find_common_elements_set(lists))  # 输出: [3]

def find_common_elements_sort(lists):
    if not lists:
        return []
    sorted_lists = [sorted(lst) for lst in lists]
    min_length = min(len(lst) for lst in sorted_lists)
    common_elements = []
    for i in range(min_length):
        current_element = sorted_lists[0][i]
        if all(current_element == lst[i] for lst in sorted_lists):
            common_elements.append(current_element)
    return common_elements

# 示例
lists = [[1, 2, 3], [2, 3, 4], [3, 4, 5]]
print(find_common_elements_sort(lists))  # 输出: [3]

def find_common_elements(lists):
    if not lists:
        return []
    # 其他逻辑