有没有一种方法可以从C++中有效地将列表一分为二的对列表中获取列表

#include <iostream>
#include <list>
#include <algorithm>

int main() {
    std::list<int> originalList = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    std::list<int> list1;
    std::list<int> list2;

    // 使用迭代器和算法将列表一分为二
    std::copy_if(originalList.begin(), originalList.end(), std::back_inserter(list1), [](int num) {
        return num % 2 == 0; // 将偶数添加到list1
    });

    std::copy_if(originalList.begin(), originalList.end(), std::back_inserter(list2), [](int num) {
        return num % 2 != 0; // 将奇数添加到list2
    });

    // 输出分割后的列表
    std::cout << "List 1: ";
    for (const auto& num : list1) {
        std::cout << num << " ";
    }
    std::cout << std::endl;

    std::cout << "List 2: ";
    for (const auto& num : list2) {
        std::cout << num << " ";
    }
    std::cout << std::endl;

    return 0;
}