接收输入字符串并返回子字符串列表和每个子字符串出现的次数

def get_substring_counts(input_str):
    # 预处理字符串，去除无关字符
    input_str = ''.join(e for e in input_str if e.isalnum())

    # 存储子字符串及其出现次数的字典
    substring_counts = {}

    # 遍历字符串获取子字符串及其出现次数
    for length in range(1, len(input_str) + 1):
        for i in range(len(input_str) - length + 1):
            substring = input_str[i:i+length]
            if substring in substring_counts:
                substring_counts[substring] += 1
            else:
                substring_counts[substring] = 1

    # 存储子字符串和出现次数的列表
    substrings = list(substring_counts.keys())
    counts = list(substring_counts.values())

    return substrings, counts

input_str = "abababa"
substrings, counts = get_substring_counts(input_str)
print("子字符串列表：", substrings)
print("出现次数列表：", counts)

子字符串列表： ['a', 'b', 'ab', 'ba', 'aba', 'bab', 'abab', 'baba', 'ababa']
出现次数列表： [4, 3, 3, 3, 2, 2, 2, 2, 1]