排除重叠时间的DateIntevals数组的持续时间

def get_duration(date_intervals):
    # Step 1: Sort the DateIntervals array by start time
    sorted_intervals = sorted(date_intervals, key=lambda x: x.start)

    # Step 2: Create an empty result array
    result = []

    # Step 3: Iterate through the sorted intervals
    for interval in sorted_intervals:
        # Step 4: Add the first interval to the result array
        if not result:
            result.append(interval)
        else:
            # Step 5: Compare the current interval with the last interval in the result array
            last_interval = result[-1]
            if interval.start > last_interval.end:
                # No overlap, add the current interval to the result array
                result.append(interval)
            else:
                # Overlap, update the end time of the last interval in the result array
                last_interval.end = max(last_interval.end, interval.end)

    # Step 6: Calculate the duration of each interval in the result array
    durations = [interval.end - interval.start for interval in result]

    # Step 7: Calculate the total duration
    total_duration = sum(durations)

    return total_duration