在Dart Flutter中将嵌套的JSON合并到简单JSON可以通过以下步骤实现:
dart:convert
库,该库提供了JSON的编码和解码功能。Map
类来表示。例如:Map<String, dynamic> simpleJson = {
"name": "John Doe",
"age": 25,
"email": "johndoe@example.com"
};
Map
类表示。例如:Map<String, dynamic> nestedJson = {
"address": {
"street": "123 Main St",
"city": "New York",
"country": "USA"
},
"phone": {
"home": "123-456-7890",
"work": "987-654-3210"
}
};
addAll()
方法。例如:simpleJson.addAll(nestedJson);
simpleJson
对象已经包含了嵌套JSON的内容。完整的示例代码如下:
import 'dart:convert';
void main() {
Map<String, dynamic> simpleJson = {
"name": "John Doe",
"age": 25,
"email": "johndoe@example.com"
};
Map<String, dynamic> nestedJson = {
"address": {
"street": "123 Main St",
"city": "New York",
"country": "USA"
},
"phone": {
"home": "123-456-7890",
"work": "987-654-3210"
}
};
simpleJson.addAll(nestedJson);
String mergedJson = jsonEncode(simpleJson);
print(mergedJson);
}
这段代码将输出合并后的JSON字符串:
{
"name": "John Doe",
"age": 25,
"email": "johndoe@example.com",
"address": {
"street": "123 Main St",
"city": "New York",
"country": "USA"
},
"phone": {
"home": "123-456-7890",
"work": "987-654-3210"
}
}
在这个例子中,我们使用了Dart的内置JSON编码器jsonEncode()
将合并后的JSON对象转换为字符串。你可以根据自己的需求进行进一步的处理或传输。
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