我应该怎么做才能将Mysql的结果抛出另一个js文件

const mysql = require('mysql2');

const connection = mysql.createConnection({
  host: 'localhost',
  user: 'your_username',
  password: 'your_password',
  database: 'your_database'
});

function executeQuery(query) {
  return new Promise((resolve, reject) => {
    connection.query(query, (error, results) => {
      if (error) {
        reject(error);
      } else {
        resolve(results);
      }
    });
  });
}

app.get('/getMysqlResults', async (req, res) => {
  try {
    const query = 'SELECT * FROM your_table';
    const results = await executeQuery(query);

    // 将结果以JSON格式发送给客户端
    res.json(results);
  } catch (error) {
    console.error(error);
    res.status(500).send('服务器内部错误');
  }
});

fetch('/getMysqlResults')
  .then(response => response.json())
  .then(results => {
    // 处理MySQL结果的代码
    console.log(results);
  })
  .catch(error => console.error(error));