我们如何一次将嵌套的json对象反序列化为python模型对象？

import json

# 定义一个模型类
class Model:
    def __init__(self, data):
        self.__dict__ = data

# 定义一个函数，用于将JSON对象反序列化为模型对象
def deserialize(json_obj):
    # 递归处理嵌套的JSON对象
    if isinstance(json_obj, dict):
        for key, value in json_obj.items():
            if isinstance(value, dict):
                json_obj[key] = deserialize(value)
            elif isinstance(value, list):
                json_obj[key] = [deserialize(item) if isinstance(item, dict) else item for item in value]
    elif isinstance(json_obj, list):
        json_obj = [deserialize(item) if isinstance(item, dict) else item for item in json_obj]
    
    # 根据数据创建模型对象
    return Model(json_obj)

# 示例JSON字符串
json_str = '''
{
    "name": "John",
    "age": 30,
    "address": {
        "street": "123 Main St",
        "city": "New York"
    },
    "phones": [
        {
            "type": "home",
            "number": "555-1234"
        },
        {
            "type": "work",
            "number": "555-5678"
        }
    ]
}
'''

# 将JSON字符串反序列化为模型对象
json_obj = json.loads(json_str)
model_obj = deserialize(json_obj)

# 使用模型对象的属性
print(model_obj.name)  # 输出：John
print(model_obj.age)  # 输出：30
print(model_obj.address.street)  # 输出：123 Main St
print(model_obj.address.city)  # 输出：New York
print(model_obj.phones[0].type)  # 输出：home
print(model_obj.phones[0].number)  # 输出：555-1234
print(model_obj.phones[1].type)  # 输出：work
print(model_obj.phones[1].number)  # 输出：555-5678