希望简化C语言中的if语句链

int value = 2;

switch (value) {
    case 1:
        printf("Value is 1\n");
        break;
    case 2:
        printf("Value is 2\n");
        break;
    case 3:
        printf("Value is 3\n");
        break;
    default:
        printf("Value is not 1, 2, or 3\n");
        break;
}

#include <stdio.h>

void func1() {
    printf("Function 1 called\n");
}

void func2() {
    printf("Function 2 called\n");
}

void func3() {
    printf("Function 3 called\n");
}

typedef void (*func_ptr)();

int main() {
    func_ptr funcs[] = {func1, func2, func3};
    int value = 1;

    if (value >= 0 && value < 3) {
        funcs[value]();
    } else {
        printf("Invalid value\n");
    }

    return 0;
}

#include <stdio.h>

typedef struct {
    int key;
    const char* message;
} LookupTable;

const LookupTable lut[] = {
    {1, "Value is 1"},
    {2, "Value is 2"},
    {3, "Value is 3"}
};

const char* getMessage(int value) {
    for (int i = 0; i < sizeof(lut) / sizeof(lut[0]); ++i) {
        if (lut[i].key == value) {
            return lut[i].message;
        }
    }
    return "Value not found";
}

int main() {
    int value = 2;
    printf("%s\n", getMessage(value));
    return 0;
}