嵌套的两种OrderedDict的比较

from collections import OrderedDict

def compare_nested_ordered_dicts(dict1, dict2):
    if len(dict1) != len(dict2):
        return False
    
    for key1, value1 in dict1.items():
        if key1 not in dict2:
            return False
        
        value2 = dict2[key1]
        
        if isinstance(value1, OrderedDict) and isinstance(value2, OrderedDict):
            if not compare_nested_ordered_dicts(value1, value2):
                return False
        elif value1 != value2:
            return False
    
    return True

# 示例用法
dict1 = OrderedDict([('a', 1), ('b', OrderedDict([('c', 2), ('d', 3)]))])
dict2 = OrderedDict([('a', 1), ('b', OrderedDict([('c', 2), ('d', 3)]))])
dict3 = OrderedDict([('a', 1), ('b', OrderedDict([('c', 2), ('d', 4)]))])

print(compare_nested_ordered_dicts(dict1, dict2))  # 输出：True
print(compare_nested_ordered_dicts(dict1, dict3))  # 输出：False