我有一个Java范围列表
public class Range {
private int min, max;
//constructor, getters, setters go here
}
所以,一张清单可能是这样的
ranges = [[3,9], [18,45], [90,112]]
我需要做以下的功能
public int getRandomValueWithinRanges() {
//returns a value which is contained inside a range inside the ranges ArrayList
}
我该怎么做?在这些
我在Java编程方面还是个新手。我刚刚了解了数组,做了几次测试,结果遇到了麻烦。
import java.util.Scanner;
class oranges {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
int user_input;
whatever whateverObject = new whatever();
System.out.println("Enter 1 to dem
我正在尝试建立一个音乐播放器,但有一个问题,从SD卡的歌曲列表。它显示了这个错误:
java.lang.IndexOutOfBoundsException: Invalid index 0, size is 0
java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:255)
下面是SongManager代码,该类应该返回songlist
public class SongsManager {
// SDCard Path
final String MEDIA_PATH =
我对Java很陌生,并试图做以下工作:
给定一个整数数组,如果数组中的整数介于70到79之间,则打印"Yes“。否则,打印“否”。
到目前为止,我的代码如下:
import java.util.Arrays;
int temperatures[] = {45, 70, 71, 67}; //create array
Arrays.sort(temperatures); //sort temperatures
int key = 70; //define key to be searched
int result = Arrays.binarySearch(temperatures,
static int binarySearch(int[] arr, int target){
int start = 0;
int end = arr.length -1;
while(start<= end){
//find the middle element
// ind mid = (start + end )/2; // might be possible that the ( start+ end ) exceeds the range of int in java if they
我需要打印32位二进制数字的所有实例,其中没有两个1s相邻。
例如:
10101010101010000000101010101010 is valid
01010101010110000000000000000000 is not because there are adjacent 1s
这是我所拥有的。
String number;
boolean valid = false;
for(int i = 0; i<= 1e32; i++)
{
//create binary number
number = Strin
我有以下mysql查询
SELECT count(order_id), date FROM tbl_order WHERE campaign_status = 'In Progress' or campaign_status = 'Pending' GROUP BY DATE_FORMAT(date,'%d %b %y')
然后执行下面的循环
<?php do { ?>
['<?php echo $row_chartData['date']; ?>', <?php echo $r
两个variable之间的区别是什么?一个被赋值为undefined,另一个被赋值declared a var not initiased?
var a = undefined;
var b;
a === b; // returns true
两个变量a和b之间有什么不同
var ar = new Array(4); // ar = 0[undefined × 4]
ar[0] = null; // ar = [null, undefined × 3]
ar[1] = undefined; // ar = [null, undefined, undefined × 2]
ar.filte
我在初始化ArrayList时遇到了令人沮丧的问题。我在binaryTreeList.set(1, root);行得到了一个错误,说
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 1, Size: 0
at java.util.ArrayList.rangeCheck(Unknown Source)
at java.util.ArrayList.set(Unknown Source)
at BinaryTreeADT.<init>(BinaryTr
在Java中有一些来自Thinking的代码
public class SimpleHashMap<K,V> extends AbstractMap<K,V> {
static final int SIZE = 997;
@SuppressWarnings("unchecked")
LinkedList<MapEntry<K,V>>[] buckets = new LinkedList[SIZE];
public V put(K key, V value) {
V oldValue