我试图将byte[]转换为long,但我得到了java.lang.NumberFormatException。String hexstring = "dba753f8a80c6608";
Long value = Long.parseLong(hexString.trim(),正确的六边形必须类似于这个"DBA753F8A80C668“
E5E9FA1BA31ECD1AE84F75CAAA474F3A".getBytes(StandardCharsets.UTF_8)))现在我正试图将"YxRfXk827kPgkmMUX15PNg==“转换为十六进制。: Illegal hexadecimal character R at index 0String guid = "YxRfXk827kPgkmMUX15PNg(hexString</