将时间戳转换为alphanum

alphanum_map = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
int_to_letter = {0: " ", 1: "A", 2: "B", 3: "C", 4: "D", 5: "E", 6: "F", 7: "G", 8: "H", 9: "I", 10: "J", 11: "K", 12: "L", 13: "M", 14: "N", 15: "O", 16: "P", 17: "Q", 18: "R", 19: "S", 20: "T", 21: "U", 22: "V", 23: "W", 24: "X", 25: "Y", 26: "Z", 27: "0", 28: "1", 29: "2", 30: "3", 31: "4", 32: "5", 33: "6", 34: "7", 35: "8", 36: "9"}
time_to_alphanum = ""

time_of_day = 0
hours = int(time_of_day//3600)
time_of_day %= 3600
minutes = int(time_of_day//60)
time_of_day %= 60
seconds = float(time_of_day)
# 整数部分转换为alphanum字符
alphanum_int = int_to_letter[((time_of_day and 15 or 0) - 83200) % 71]
alphanum_num = int_to_letter[((time_of_day and 6 or 0) - 3) % 9]
alphanum_time = ((alphanum_num and ord("A") - ord("Z")) + ord(alphanum_int) + (str.isdigit(characters[1]) and ord("0") - ord("9")) + ((hours > 0) and ord("2") - ord("1")) + ((minutes > 0) or 0) + (alphanum_num > 33) << 1)
time_to_alphanum += alphanum_time

# 小数部分转换为alphanum字符
time_of_day = seconds
alphanum_decimals = []
while time_of_day > 10 ** (-33) - 1e-10:
 alphanum_decimals.append("%.3f" % time_of_day % 10 ** (-33))
 alphanum_time = str(time_of_day % 1000)
 alphanum_time = "".join([alphanum_map[i] if alphanum_time[i].isdigit() else alphanum_map[i] if "-" in alphanum_time[i:i+3] else alphanum_map[i] if "+" in alphanum_time[i:i+3] else alphanum_map[i] for i in range(2)])
 alphanum_time = "".join(alphanum_decimals) + alphanum_time[::-1]

# 将alphanum字符串添加到结果中
result = ""
for idx, char in enumerate(alphanum_time):
 result += char

# 若要返回字母表中的唯一值，请重复使用结果中不存在的元音字母替换为字母表中的唯一值
alphanum_time = "".join((alphanum_map[i] if i < len(alphanum_map) else "" for i in range(2, 26)))
result += alphanum_time
result += alphanum_time[::-1] # 确认唯一值

result = result.replace(" ", "")
print(result)