对格式不佳的12小时时间数据的条件调整

import re
from datetime import datetime

def convert_time(time_str):
    # 使用正则表达式匹配12小时制时间格式
    match = re.match(r'(\d{1,2}):(\d{2})([AP]M)', time_str, re.IGNORECASE)
    if match:
        hour, minute, am_pm = match.groups()
        hour = int(hour)
        if am_pm.lower() == 'pm' and hour != 12:
            hour += 12
        elif am_pm.lower() == 'am' and hour == 12:
            hour = 0
        return datetime.strptime(f"{hour}:{minute}", "%H:%M").strftime("%Y-%m-%d %H:%M:%S")
    else:
        return None

# 示例数据
time_data = ["3:45pm", "1:23 P.M.", "9:15am"]
converted_data = [convert_time(t) for t in time_data]
print(converted_data)