如果列表在多个方向上有4个连续的数字，则获取真或假结果

def check_consecutive_numbers(matrix):
    rows = len(matrix)
    cols = len(matrix[0])

    # 检查水平方向
    for i in range(rows):
        for j in range(cols - 3):
            if matrix[i][j] == matrix[i][j+1] == matrix[i][j+2] == matrix[i][j+3]:
                return True

    # 检查垂直方向
    for i in range(rows - 3):
        for j in range(cols):
            if matrix[i][j] == matrix[i+1][j] == matrix[i+2][j] == matrix[i+3][j]:
                return True

    # 检查对角线方向（左上到右下）
    for i in range(rows - 3):
        for j in range(cols - 3):
            if matrix[i][j] == matrix[i+1][j+1] == matrix[i+2][j+2] == matrix[i+3][j+3]:
                return True

    # 检查对角线方向（右上到左下）
    for i in range(rows - 3):
        for j in range(3, cols):
            if matrix[i][j] == matrix[i+1][j-1] == matrix[i+2][j-2] == matrix[i+3][j-3]:
                return True

    return False

# 示例输入
matrix = [
    [1, 2, 3, 4, 5],
    [6, 7, 8, 9, 10],
    [11, 12, 13, 14, 15],
    [16, 17, 18, 19, 20],
    [21, 22, 23, 24, 25]
]

# 调用函数并打印结果
print(check_consecutive_numbers(matrix))