如何重构函数，使其在列表中只返回1个True值？

def find_true(lst):
    return any(lst)

# 示例
lst = [False, False, True, False]
result = find_true(lst)
print(result)  # 输出: True

def find_true(lst):
    return next((x for x in lst if x), False)

# 示例
lst = [False, False, True, False]
result = find_true(lst)
print(result)  # 输出: True

def find_true(lst):
    for item in lst:
        if item:
            return True
    return False

# 示例
lst = [False, False, True, False]
result = find_true(lst)
print(result)  # 输出: True

def find_true(lst):
    return next(filter(None, lst), False)

# 示例
lst = [False, False, True, False]
result = find_true(lst)
print(result)  # 输出: True

def find_all_trues(lst):
    return [i for i, x in enumerate(lst) if x]

# 示例
lst = [False, False, True, False, True]
result = find_all_trues(lst)
print(result)  # 输出: [2, 4]