如何通过flask从python脚本返回确切的错误

from flask import Flask, abort

app = Flask(__name__)

@app.route('/')
def index():
    try:
        # 执行一些可能出错的代码
        result = 1 / 0
        return 'Success'
    except Exception as e:
        # 返回具体的错误信息和状态码
        abort(500, str(e))

pip install flask_restful

from flask import Flask
from flask_restful import Api, Resource

app = Flask(__name__)
api = Api(app)

class Index(Resource):
    def get(self):
        try:
            # 执行一些可能出错的代码
            result = 1 / 0
            return {'message': 'Success'}
        except Exception as e:
            # 返回具体的错误信息和状态码
            return {'error': str(e)}, 500

api.add_resource(Index, '/')

if __name__ == '__main__':
    app.run()