如何让路径的所有可能性都以特定的开头出现？

def find_paths(current_path, target_path):
    if current_path == target_path[:len(current_path)]:
        # 当前路径与目标路径的开头匹配，将当前路径添加到结果集中
        result.append(current_path)
    
    if len(current_path) == len(target_path):
        # 已经遍历完所有可能性，返回
        return
    
    if len(current_path) < len(target_path):
        # 继续递归调用函数，遍历所有可能的下一个字符
        for char in ['A', 'B', 'C']:
            find_paths(current_path + char, target_path)

# 测试示例
result = []
find_paths('', 'ABC')
print(result)