如何解构包含以点为键的长字符串的对象

const objString = '{"a.b.c": 1, "a.b.d": 2, "e.f": 3}';
const obj = JSON.parse(objString);

const result = {};

function destructureObject(obj, result) {
  for (let key in obj) {
    if (obj.hasOwnProperty(key)) {
      const keys = key.split('.');
      let currentObj = result;
      
      for (let i = 0; i < keys.length; i++) {
        const currentKey = keys[i];
        
        if (!currentObj.hasOwnProperty(currentKey)) {
          currentObj[currentKey] = {};
        }
        
        if (i === keys.length - 1) {
          currentObj[currentKey] = obj[key];
        } else {
          currentObj = currentObj[currentKey];
        }
      }
    }
  }
}

destructureObject(obj, result);

console.log(result.a.b.c); // 输出: 1
console.log(result.a.b.d); // 输出: 2
console.log(result.e.f); // 输出: 3