如何获取参数以忽略部分消息

const urlParams = new URLSearchParams(window.location.search);
const name = urlParams.get('name'); // "John"
const age = urlParams.get('age'); // "30"

<form id="myForm">
  <label for="name">Name:</label>
  <input type="text" id="name" name="name">
  <label for="age">Age:</label>
  <input type="text" id="age" name="age">
  <button type="submit">Submit</button>
</form>

const form = document.getElementById('myForm');
form.addEventListener('submit', function(event) {
  event.preventDefault(); // 阻止表单提交
  const name = document.getElementById('name').value;
  const age = document.getElementById('age').value;
  // 处理获取到的参数值
});

<button id="myButton" data-name="John" data-age="30">Click me</button>

const button = document.getElementById('myButton');
button.addEventListener('click', function() {
  const name = button.getAttribute('data-name');
  const age = button.getAttribute('data-age');
  // 处理获取到的参数值
});

app.get('/', function(req, res) {
  const name = req.query.name; // "John"
  const age = req.query.age; // "30"
  // 处理获取到的参数值
});

const bodyParser = require('body-parser');
app.use(bodyParser.json());

app.post('/', function(req, res) {
  const name = req.body.name;
  const age = req.body.age;
  // 处理获取到的参数值
});

app.get('/user/:id', function(req, res) {
  const userId = req.params.id;
  // 处理获取到的参数值
});