如何按年、月、日对事件列表进行分组

import datetime

# 假设事件列表为一个包含日期字段的列表
event_list = [
    {"event": "事件1", "date": "2022-01-01"},
    {"event": "事件2", "date": "2022-01-02"},
    {"event": "事件3", "date": "2022-02-01"},
    {"event": "事件4", "date": "2022-02-02"},
    # 其他事件...
]

# 定义一个字典，用于按年、月、日分组存储事件
grouped_events = {}

# 遍历事件列表
for event in event_list:
    # 解析日期字段
    date_str = event["date"]
    date = datetime.datetime.strptime(date_str, "%Y-%m-%d")
    
    # 提取年、月、日信息
    year = date.year
    month = date.month
    day = date.day
    
    # 按年、月、日分组存储事件
    if year not in grouped_events:
        grouped_events[year] = {}
    if month not in grouped_events[year]:
        grouped_events[year][month] = {}
    if day not in grouped_events[year][month]:
        grouped_events[year][month][day] = []
    
    grouped_events[year][month][day].append(event)

# 打印分组结果
for year, months in grouped_events.items():
    for month, days in months.items():
        for day, events in days.items():
            print(f"{year}-{month}-{day}:")
            for event in events:
                print(event["event"])
            print()