如何将连续的几天按ids分组？

def group_continuous_days_by_ids(data):
    # Step 2: Sort the data by date
    sorted_data = sorted(data, key=lambda x: x[0])

    # Step 3: Initialize the result list
    result = []

    # Step 4: Group the data by continuous days
    current_group = [sorted_data[0][1]]
    for i in range(1, len(sorted_data)):
        if (sorted_data[i][0] - sorted_data[i-1][0]).days == 1:
            current_group.append(sorted_data[i][1])
        else:
            result.append(current_group)
            current_group = [sorted_data[i][1]]
    result.append(current_group)

    return result

# Example usage
data = [(date(2022, 1, 1), 1), (date(2022, 1, 2), 2), (date(2022, 1, 3), 3), (date(2022, 1, 5), 4), (date(2022, 1, 6), 5)]
result = group_continuous_days_by_ids(data)
print(result)