如何按日期分组并查找连续天数

def group_continuous_dates(dates):
    sorted_dates = sorted(dates)
    result = []
    group = [sorted_dates[0]]

    for i in range(1, len(sorted_dates)):
        if (sorted_dates[i] - sorted_dates[i-1]).days == 1:
            group.append(sorted_dates[i])
        else:
            result.append(group)
            group = [sorted_dates[i]]

    result.append(group)
    return result

# 示例数据
dates = [date(2022, 1, 1), date(2022, 1, 2), date(2022, 1, 3), date(2022, 1, 5), date(2022, 1, 6), date(2022, 1, 8)]

# 按日期分组并查找连续天数
result = group_continuous_dates(dates)

# 输出结果
for group in result:
    print(group)