如何将两个数组的差异合并为一个

function mergeDifferences(arr1, arr2) {
  const set1 = new Set(arr1);
  const set2 = new Set(arr2);

  const diff1 = [...set1].filter(x => !set2.has(x));
  const diff2 = [...set2].filter(x => !set1.has(x));

  return [...diff1, ...diff2];
}

// 示例
const arr1 = [1, 2, 3, 4];
const arr2 = [3, 4, 5, 6];
console.log(mergeDifferences(arr1, arr2)); // 输出: [1, 2, 5, 6]

const _ = require('lodash');

function mergeDifferences(arr1, arr2) {
  return _.xor(arr1, arr2);
}

// 示例
const arr1 = [1, 2, 3, 4];
const arr2 = [3, 4, 5, 6];
console.log(mergeDifferences(arr1, arr2)); // 输出: [1, 2, 5, 6]

function mergeDifferences(arr1, arr2, compareFn) {
  const diff1 = arr1.filter(x => !arr2.some(y => compareFn(x, y)));
  const diff2 = arr2.filter(x => !arr1.some(y => compareFn(x, y)));

  return [...diff1, ...diff2];
}

// 示例
const arr1 = [{ id: 1, name: 'A' }, { id: 2, name: 'B' }];
const arr2 = [{ id: 2, name: 'B' }, { id: 3, name: 'C' }];

const compareFn = (a, b) => a.id === b.id;
console.log(mergeDifferences(arr1, arr2, compareFn)); // 输出: [{ id: 1, name: 'A' }, { id: 3, name: 'C' }]