如何处理重叠和删除作为任何单词的子串的单词？

import re

def remove_substrings(words, substrings):
    pattern = '|'.join(map(re.escape, substrings))
    regex = re.compile(pattern)
    cleaned_words = [regex.sub('', word) for word in words]
    return cleaned_words

# 示例
words = ["book", "booking", "car", "automobile"]
substrings_to_remove = ["ook", "auto"]
cleaned_words = remove_substrings(words, substrings_to_remove)
print(cleaned_words)  # 输出: ['b', 'bkng', 'car', 'mobile']

def filter_overlapping_words(words, substrings):
    filtered_words = []
    seen_substrings = set(substrings)
    for word in words:
        if not any(substring in word for substring in seen_substrings):
            filtered_words.append(word)
    return filtered_words

# 示例
words = ["book", "booking", "car", "automobile"]
substrings_to_filter = ["ook", "auto"]
filtered_words = filter_overlapping_words(words, substrings_to_filter)
print(filtered_words)  # 输出: ['car']