如何在scrapy response.follow中做一个循环？

import scrapy

class MySpider(scrapy.Spider):
    name = 'my_spider'
    start_urls = ['http://example.com']

    def parse(self, response):
        # 获取需要跟随的链接列表
        links = response.css('a::attr(href)').getall()

        for link in links:
            # 构造新的请求，并跟随链接进行爬取
            yield response.follow(link, callback=self.parse_link)

    def parse_link(self, response):
        # 处理跟随链接的响应数据
        # ...

        # 继续在跟随链接的页面中进行循环
        yield from self.parse(response)