如何在sapui5动态表上获取项目？

// 视图文件（view.xml）
<mvc:View xmlns:mvc="sap.ui.core.mvc" xmlns:core="sap.ui.core" xmlns:m="sap.m" xmlns:table="sap.ui.table">
    <table:Table id="myTable" visibleRowCount="10" selectionMode="None">
        <!-- 表格列定义 -->
        <table:columns>
            <table:Column>
                <m:Label text="项目ID"/>
                <table:template>
                    <m:Text text="{projectID}"/>
                </table:template>
            </table:Column>
            <table:Column>
                <m:Label text="项目名称"/>
                <table:template>
                    <m:Text text="{projectName}"/>
                </table:template>
            </table:Column>
            <!-- 其他列定义 -->
        </table:columns>
    </table:Table>
</mvc:View>

// 控制器文件（controller.js）
sap.ui.define([
    "sap/ui/core/mvc/Controller",
    "sap/ui/model/json/JSONModel",
    "sap/ui/model/odata/v2/ODataModel"
], function(Controller, JSONModel, ODataModel) {
    "use strict";

    return Controller.extend("your.app.namespace.controller.Main", {
        onInit: function() {
            // 获取项目数据
            this._getProjects();
        },

        _getProjects: function() {
            var oModel = new ODataModel("your/service/url"); // 替换为实际的OData服务URL
            var that = this;

            oModel.read("/Projects", {
                success: function(oData) {
                    var oTable = that.getView().byId("myTable");
                    var oTableData = {
                        projects: oData.results
                    };
                    var oTableModel = new JSONModel(oTableData);

                    oTable.setModel(oTableModel);
                },
                error: function(oError) {
                    // 处理错误
                }
            });
        }
    });
});