如何在python中生成路径列表的树形结构字典

import os

def generate_tree(root_path):
    tree = {'name': os.path.basename(root_path)}
    if os.path.isfile(root_path):
        tree['type'] = 'file'
    else:
        tree['type'] = 'directory'
        tree['children'] = []
        for filename in os.listdir(root_path):
            file_path = os.path.join(root_path, filename)
            tree['children'].append(generate_tree(file_path))
    return tree

# 示例用法
root_path = '/path/to/directory'
tree = generate_tree(root_path)
print(tree)