如何在python中分隔一些重叠的时间段？

from datetime import datetime

def separate_overlapping_intervals(time_intervals):
    sorted_intervals = sorted(time_intervals, key=lambda x: datetime.strptime(x[0], "%Y-%m-%d %H:%M:%S"))
    separated_intervals = []
    current_interval = sorted_intervals[0]

    for interval in sorted_intervals[1:]:
        start_time = datetime.strptime(interval[0], "%Y-%m-%d %H:%M:%S")
        end_time = datetime.strptime(interval[1], "%Y-%m-%d %H:%M:%S")

        if start_time <= current_interval[1]:
            current_interval = (current_interval[0], max(current_interval[1], end_time))
        else:
            separated_intervals.append(current_interval)
            current_interval = interval

    separated_intervals.append(current_interval)
    return separated_intervals

time_intervals = [("2022-01-01 09:00:00", "2022-01-01 10:00:00"),
                  ("2022-01-01 09:30:00", "2022-01-01 11:00:00"),
                  ("2022-01-01 12:00:00", "2022-01-01 13:00:00")]

separated_intervals = separate_overlapping_intervals(time_intervals)
print(separated_intervals)

[('2022-01-01 09:00:00', '2022-01-01 11:00:00'), ('2022-01-01 12:00:00', '2022-01-01 13:00:00')]