如何在Spring中将带有数据的XML解析成DB？

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.stereotype.Component;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import java.io.File;

@Component
public class XmlParser {
    private final JdbcTemplate jdbcTemplate;

    @Autowired
    public XmlParser(JdbcTemplate jdbcTemplate) {
        this.jdbcTemplate = jdbcTemplate;
    }

    public void parseXmlToDb(String xmlFilePath) {
        try {
            // 创建解析器工厂
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            // 创建解析器
            DocumentBuilder builder = factory.newDocumentBuilder();
            // 解析XML文件
            Document document = builder.parse(new File(xmlFilePath));
            // 获取根节点
            Element root = document.getDocumentElement();
            // 获取所有数据节点
            NodeList dataList = root.getElementsByTagName("data");

            for (int i = 0; i < dataList.getLength(); i++) {
                Node dataNode = dataList.item(i);
                if (dataNode.getNodeType() == Node.ELEMENT_NODE) {
                    Element dataElement = (Element) dataNode;
                    // 解析数据节点的属性和值
                    String id = dataElement.getAttribute("id");
                    String name = dataElement.getAttribute("name");
                    String value = dataElement.getTextContent();

                    // 将数据持久化到数据库
                    jdbcTemplate.update("INSERT INTO table_name (id, name, value) VALUES (?, ?, ?)", id, name, value);
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}