如何在React Native中将弹出菜单与TouchableOpacity相结合？

import React, { useState } from 'react';
import { View, TouchableOpacity, Text, StyleSheet } from 'react-native';

const PopupMenu = () => {
  const [isMenuVisible, setMenuVisible] = useState(false);

  const toggleMenu = () => {
    setMenuVisible(!isMenuVisible);
  };

  return (
    <View style={styles.container}>
      <TouchableOpacity onPress={toggleMenu}>
        <Text>点击打开菜单</Text>
      </TouchableOpacity>

      {isMenuVisible && (
        <View style={styles.menu}>
          <TouchableOpacity onPress={() => console.log('选项1被点击')}>
            <Text>选项1</Text>
          </TouchableOpacity>
          <TouchableOpacity onPress={() => console.log('选项2被点击')}>
            <Text>选项2</Text>
          </TouchableOpacity>
          <TouchableOpacity onPress={() => console.log('选项3被点击')}>
            <Text>选项3</Text>
          </TouchableOpacity>
        </View>
      )}
    </View>
  );
};

const styles = StyleSheet.create({
  container: {
    flex: 1,
    justifyContent: 'center',
    alignItems: 'center',
  },
  menu: {
    position: 'absolute',
    top: 50,
    right: 10,
    backgroundColor: '#fff',
    padding: 10,
    borderRadius: 5,
    elevation: 3,
  },
});