如何在Python中查找列表中恰好出现2次的元素的索引

def find_elements_appear_twice(lst):
    # 统计每个元素的出现次数
    count_dict = {}
    for element in lst:
        if element in count_dict:
            count_dict[element] += 1
        else:
            count_dict[element] = 1
    
    # 找出恰好出现两次的元素及其索引
    result = {}
    for element, count in count_dict.items():
        if count == 2:
            result[element] = [i for i, x in enumerate(lst) if x == element]
    
    return result

# 示例列表
lst = [1, 2, 3, 2, 4, 3]
result = find_elements_appear_twice(lst)
print(result)

{2: [1, 3], 3: [2, 5]}