如何在Python中使用regex删除URL的一部分？

import re

def remove_url_part(url, pattern):
    result = re.sub(pattern, '', url)
    return result

url = "https://www.example.com/path/to/your/destination/page?query=parameters"

# 删除查询参数之前的部分
pattern = r'https?://www\.example\.com/path/to/your/destination/'
new_url = remove_url_part(url, pattern)

print(new_url)

page?query=parameters