如何在List.map()函数中等待将来并返回字符串列表

async def process_item(item):
    # 模拟异步操作，例如从数据库中获取数据
    await asyncio.sleep(1)
    return str(item)

async def main():
    items = [1, 2, 3, 4, 5]
    results = await asyncio.gather(*[process_item(item) for item in items])
    return results

result = asyncio.run(main())
print(result)

import asyncio

async def process_item(item):
    await asyncio.sleep(1)
    return str(item)

async def main():
    items = [1, 2, 3, 4, 5]
    results = await asyncio.gather(*map(process_item, items))
    return results

result = asyncio.run(main())
print(result)