如何在DataGridView中从ComboBoxColumn中选择项目时显示表的属性。？

// 创建一个DataGridView
DataGridView dataGridView = new DataGridView();

// 添加一个ComboBoxColumn
DataGridViewComboBoxColumn comboBoxColumn = new DataGridViewComboBoxColumn();
dataGridView.Columns.Add(comboBoxColumn);

// 设置ComboBoxColumn的数据源
comboBoxColumn.DataSource = yourDataSource;

// 设置ComboBoxColumn的DisplayMember和ValueMember属性
comboBoxColumn.DisplayMember = "PropertyName";
comboBoxColumn.ValueMember = "PropertyValue";

// 为DataGridView的CellFormatting事件添加处理程序
dataGridView.CellFormatting += DataGridView_CellFormatting;

// CellFormatting事件处理程序
private void DataGridView_CellFormatting(object sender, DataGridViewCellFormattingEventArgs e)
{
    // 判断当前列是否为ComboBoxColumn，并且当前单元格的值不为空
    if (dataGridView.Columns[e.ColumnIndex] is DataGridViewComboBoxColumn && e.Value != null)
    {
        // 获取ComboBoxColumn的数据源
        var dataSource = ((DataGridViewComboBoxColumn)dataGridView.Columns[e.ColumnIndex]).DataSource;

        // 根据当前单元格的值找到对应的属性值
        var propertyValue = dataSource.AsEnumerable()
            .FirstOrDefault(row => row.Field<string>("PropertyValue") == e.Value.ToString())
            ?.Field<string>("PropertyName");

        // 将属性值赋给当前单元格的显示值
        if (propertyValue != null)
        {
            e.Value = propertyValue;
            e.FormattingApplied = true;
        }
    }
}