如何在C++11中完成前一个迭代线程的情况下，每X秒创建一次线程？

#include <iostream>
#include <thread>
#include <chrono>
#include <mutex>
#include <condition_variable>

std::mutex mtx;
std::condition_variable cv;
bool ready = false;

void worker(int id) {
    std::unique_lock<std::mutex> lock(mtx);
    while (!ready) {
        cv.wait(lock);
    }
    lock.unlock();

    // 在这里执行每X秒需要执行的操作
    std::cout << "Thread " << id << " is running." << std::endl;

    std::this_thread::sleep_for(std::chrono::seconds(1)); // 模拟操作时间

    lock.lock();
    ready = false;
    cv.notify_all();
}

int main() {
    const int numOfThreads = 5;
    const int interval = 5; // X秒

    std::thread threads[numOfThreads];

    for (int i = 0; i < numOfThreads; ++i) {
        threads[i] = std::thread(worker, i);
    }

    std::this_thread::sleep_for(std::chrono::seconds(interval)); // 等待第一个间隔
    std::unique_lock<std::mutex> lock(mtx);
    ready = true;
    lock.unlock();
    cv.notify_all();

    for (int i = 0; i < numOfThreads; ++i) {
        threads[i].join();
    }

    return 0;
}