如何在返回布尔值之前先等待改造响应

async function fetchData() {
  const response = await fetch('https://example.com/api/data');
  const data = await response.json();
  // 进行改造响应的操作
  return true;
}

fetchData().then(result => {
  console.log(result); // 输出布尔值true
});

function fetchData() {
  return new Promise((resolve, reject) => {
    // 执行改造响应的异步操作
    setTimeout(() => {
      resolve(true);
    }, 1000);
  });
}

fetchData().then(result => {
  console.log(result); // 输出布尔值true
});

function fetchData() {
  return new Promise((resolve, reject) => {
    // 执行改造响应的异步操作
    setTimeout(() => {
      resolve(true);
    }, 1000);
  });
}

test('测试改造响应', async () => {
  const result = await fetchData();
  expect(result).toBe(true);
});