如何在未选中js的情况下切换栏

<div class="tab-container">
  <button class="tab-button" onclick="openTab(event, 'tab1')">Tab 1</button>
  <button class="tab-button" onclick="openTab(event, 'tab2')">Tab 2</button>
  <button class="tab-button" onclick="openTab(event, 'tab3')">Tab 3</button>
</div>

<div id="tab1" class="tab-content">
  <!-- Tab 1 content -->
</div>

<div id="tab2" class="tab-content">
  <!-- Tab 2 content -->
</div>

<div id="tab3" class="tab-content">
  <!-- Tab 3 content -->
</div>

.tab-container {
  display: flex;
}

.tab-button {
  background-color: #ccc;
  border: none;
  padding: 10px 20px;
  cursor: pointer;
}

.tab-content {
  display: none;
}

.tab-content:first-child {
  display: block;
}

function openTab(event, tabName) {
  var i, tabContent, tabButton;

  // 获取所有tab内容和tab按钮
  tabContent = document.getElementsByClassName("tab-content");
  tabButton = document.getElementsByClassName("tab-button");

  // 隐藏所有tab内容
  for (i = 0; i < tabContent.length; i++) {
    tabContent[i].style.display = "none";
  }

  // 移除所有tab按钮的active类
  for (i = 0; i < tabButton.length; i++) {
    tabButton[i].className = tabButton[i].className.replace(" active", "");
  }

  // 显示当前选中的tab内容
  document.getElementById(tabName).style.display = "block";

  // 添加active类到当前选中的tab按钮
  event.currentTarget.className += " active";
}