如何在不删除包含列表A的列表的内容的情况下删除列表A的所有内容？

list_A = [1, 2, 3]
list_B = [list_A, 'other data']

# 清空列表A
list_A.clear()

print(list_B)  # 输出: [[], 'other data']

list_A = [1, 2, 3]
list_B = [list_A, 'other data']

# 替换列表A的内容
list_A[:] = [None] * len(list_A)

print(list_B)  # 输出: [[None, None, None], 'other data']

list_A = [1, 2, 3]
list_B = [list_A, 'other data']

# 删除列表A中的所有2
list_A = [x for x in list_A if x != 2]

print(list_B)  # 输出: [[1, 3], 'other data']

list_A = [1, 2, 3]
list_B = [list_A, 'other data']

# 错误的做法：这将改变list_B中的第一个元素
list_B[0].clear()

print(list_A)  # 输出: []

list_A.clear()