如何在Haskell中删除列表中的内容

removeElement :: Eq a => a -> [a] -> [a]
removeElement x = filter (/= x)

main = do
  let list = [1, 2, 3, 4, 3, 5]
  print $ removeElement 3 list  -- 输出: [1,2,4,5]

removeIf :: (a -> Bool) -> [a] -> [a]
removeIf predicate = filter (not . predicate)

main = do
  let list = [1, 2, 3, 4, 5]
  print $ removeIf even list  -- 输出: [1,3,5]

import Data.List (deleteFirstsBy)

removeSublist :: Eq a => [a] -> [a] -> [a]
removeSublist subList list = deleteFirstsBy (==) subList list

main = do
  let list = [1, 2, 3, 4, 5]
  print $ removeSublist [2, 3] list  -- 输出: [1,4,5]

import Data.List (nub)

removeDuplicates :: Eq a => [a] -> [a]
removeDuplicates = nub

main = do
  let list = [1, 2, 2, 3, 4, 4, 5]
  print $ removeDuplicates list  -- 输出: [1,2,3,4,5]