如何在不使用向上转换的情况下编写(string*obj)列表

def create_list(strings, objects):
    result = []
    for i in range(len(strings)):
        item = {'string': strings[i], 'object': objects[i]}
        result.append(item)
    return result

# 示例调用
strings = ['string1', 'string2', 'string3']
objects = [obj1, obj2, obj3]  # obj1, obj2, obj3 为实际的对象
result_list = create_list(strings, objects)