如何区分两个文件,但忽略Perl/C/C++注释中的差异？

import re

def compare_files(file1, file2):
    with open(file1, 'r') as f1, open(file2, 'r') as f2:
        content1 = f1.read()
        content2 = f2.read()

        # 忽略Perl/C/C++注释
        content1 = re.sub(r'#.*?\n', '', content1)
        content2 = re.sub(r'#.*?\n', '', content2)
        content1 = re.sub(r'//.*?\n', '', content1)
        content2 = re.sub(r'//.*?\n', '', content2)
        content1 = re.sub(r'/\*.*?\*/', '', content1, flags=re.DOTALL)
        content2 = re.sub(r'/\*.*?\*/', '', content2, flags=re.DOTALL)

        if content1 == content2:
            return True
        else:
            return False