如何删除满足一定条件的向量中的所有元组？

# 原始列表
vector = [(1, 'a'), (2, 'b'), (1, 'c'), (3, 'd')]

# 条件：删除第一个元素为1的所有元组
filtered_vector = [tup for tup in vector if tup[0] != 1]

print(filtered_vector)  # 输出: [(2, 'b'), (3, 'd')]

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        List<Tuple> vector = new ArrayList<>();
        vector.add(new Tuple(1, "a"));
        vector.add(new Tuple(2, "b"));
        vector.add(new Tuple(1, "c"));
        vector.add(new Tuple(3, "d"));

        // 条件：删除第一个元素为1的所有元组
        vector.removeIf(tup -> tup.getFirst() == 1);

        vector.forEach(System.out::println);  // 输出: Tuple{first=2, second='b'}, Tuple{first=3, second='d'}
    }
}

class Tuple {
    private int first;
    private String second;

    public Tuple(int first, String second) {
        this.first = first;
        this.second = second;
    }

    public int getFirst() {
        return first;
    }

    public String getSecond() {
        return second;
    }

    @Override
    public String toString() {
        return "Tuple{" +
                "first=" + first +
                ", second='" + second + '\'' +
                '}';
    }
}

// 原始数组
let vector = [[1, 'a'], [2, 'b'], [1, 'c'], [3, 'd']];

// 条件：删除第一个元素为1的所有元组
let filteredVector = vector.filter(tup => tup[0] !== 1);

console.log(filteredVector);  // 输出: [ [ 2, 'b' ], [ 3, 'd' ] ]