如何使用pyton按对象列表中的两个属性进行分组

from itertools import groupby

class MyObject:
    def __init__(self, attr1, attr2, value):
        self.attr1 = attr1
        self.attr2 = attr2
        self.value = value

# 假设我们有一个对象列表
objects = [
    MyObject('a', 'x', 1),
    MyObject('a', 'x', 2),
    MyObject('a', 'y', 3),
    MyObject('b', 'x', 4),
    MyObject('b', 'y', 5)
]

# 按照attr1和attr2排序
sorted_objects = sorted(objects, key=lambda obj: (obj.attr1, obj.attr2))

# 使用groupby进行分组
groups = {}
for key, group in groupby(sorted_objects, key=lambda obj: (obj.attr1, obj.attr2)):
    groups[key] = list(group)

print(groups)

from collections import defaultdict

class MyObject:
    def __init__(self, attr1, attr2, value):
        self.attr1 = attr1
        self.attr2 = attr2
        self.value = value

# 假设我们有一个对象列表
objects = [
    MyObject('a', 'x', 1),
    MyObject('a', 'x', 2),
    MyObject('a', 'y', 3),
    MyObject('b', 'x', 4),
    MyObject('b', 'y', 5)
]

# 使用defaultdict进行分组
groups = defaultdict(list)
for obj in objects:
    groups[(obj.attr1, obj.attr2)].append(obj)

print(dict(groups))