如何使用jackson解析具有可变秒数的RFC3339时间戳

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.5</version>
</dependency>

import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;

public class MyData {
    @JsonProperty("timestamp")
    @JsonDeserialize(using = Rfc3339Deserializer.class)
    private Instant timestamp;
    
    // Getters and setters
}

import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;

import java.io.IOException;
import java.time.Instant;
import java.time.format.DateTimeFormatter;

public class Rfc3339Deserializer extends JsonDeserializer<Instant> {
    private static final DateTimeFormatter FORMATTER = DateTimeFormatter.ISO_OFFSET_DATE_TIME;

    @Override
    public Instant deserialize(JsonParser parser, DeserializationContext context) throws IOException {
        String timestamp = parser.getText();
        // 处理具有可变秒数的RFC3339时间戳
        // 例如，可以使用DateTimeFormatter解析时间戳字符串，并将其转换为Instant对象
        return Instant.from(FORMATTER.parse(timestamp));
    }
}

import com.fasterxml.jackson.databind.ObjectMapper;

public class Main {
    public static void main(String[] args) throws IOException {
        String json = "{\"timestamp\":\"2022-01-01T10:20:30.123456789Z\"}";

        ObjectMapper objectMapper = new ObjectMapper();
        MyData myData = objectMapper.readValue(json, MyData.class);

        System.out.println(myData.getTimestamp()); // 输出解析后的时间戳
    }
}