使用JSON动态创建POJO可以通过以下步骤实现:
以下是一个示例代码,使用Jackson库实现动态创建POJO的过程:
import com.fasterxml.jackson.databind.ObjectMapper;
public class DynamicPOJOExample {
public static void main(String[] args) {
String json = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";
try {
ObjectMapper objectMapper = new ObjectMapper();
MyPOJO myPOJO = objectMapper.readValue(json, MyPOJO.class);
System.out.println("Name: " + myPOJO.getName());
System.out.println("Age: " + myPOJO.getAge());
System.out.println("City: " + myPOJO.getCity());
} catch (Exception e) {
e.printStackTrace();
}
}
}
class MyPOJO {
private String name;
private int age;
private String city;
// Getters and setters
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
}
在上述示例中,我们使用Jackson库将JSON字符串解析为MyPOJO类的对象。然后,我们可以通过调用MyPOJO对象的方法来获取和操作属性值。
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