如何从.gitlab-ci.yml文件中提取单个管道名称？

import requests
import yaml

def get_pipeline_name(project_id, file_path):
    # 使用GitLab的API获取.gitlab-ci.yml文件的内容
    url = f"https://gitlab.example.com/api/v4/projects/{project_id}/repository/files/{file_path}"
    response = requests.get(url)
    file_content = response.json()["content"]

    # 解析获取到的文件内容
    yaml_data = yaml.safe_load(base64.b64decode(file_content))

    # 获取管道名称
    pipeline_name = yaml_data["pipelines"][0]["name"]

    return pipeline_name

# 示例用法
project_id = 1234
file_path = ".gitlab-ci.yml"
pipeline_name = get_pipeline_name(project_id, file_path)
print(pipeline_name)