如何从目录中仅读取以某些字符开头并根据最后4个字母分配df名称的文件？

import os

def process_files(directory, startswith_chars):
    # 获取目录下所有文件列表
    file_list = os.listdir(directory)

    # 过滤文件名并分配df名称
    df_names = {}
    for filename in file_list:
        if filename.startswith(startswith_chars):
            last_4_chars = filename[-4:]
            if last_4_chars not in df_names:
                df_names[last_4_chars] = []
            df_names[last_4_chars].append(filename)

    # 打印结果
    for df_name, filenames in df_names.items():
        print("df名称: {}".format(df_name))
        print("文件列表:")
        for filename in filenames:
            print(filename)
        print()

# 示例调用
process_files('/path/to/directory', 'abc')