如何从基类的向量中获取派生类的名称

#include <iostream>
#include <vector>
#include <typeinfo>

class Base {
public:
    virtual ~Base() {}
};

class Derived1 : public Base {
public:
    void printName() {
        std::cout << "Derived1" << std::endl;
    }
};

class Derived2 : public Base {
public:
    void printName() {
        std::cout << "Derived2" << std::endl;
    }
};

int main() {
    std::vector<Base*> vec;
    vec.push_back(new Derived1());
    vec.push_back(new Derived2());

    for (Base* obj : vec) {
        if (Derived1* derived1 = dynamic_cast<Derived1*>(obj)) {
            derived1->printName();
            const std::type_info& typeInfo = typeid(*derived1);
            std::cout << "Derived class name: " << typeInfo.name() << std::endl;
        }
        else if (Derived2* derived2 = dynamic_cast<Derived2*>(obj)) {
            derived2->printName();
            const std::type_info& typeInfo = typeid(*derived2);
            std::cout << "Derived class name: " << typeInfo.name() << std::endl;
        }
    }

    // 清理内存
    for (Base* obj : vec) {
        delete obj;
    }

    return 0;
}