如何从任意日期开始分配一年中的日期值并处理缺少的值？

import datetime

def allocate_dates(start_date, end_date):
    date_list = []
    current_date = start_date

    while current_date <= end_date:
        date_list.append(current_date)
        current_date += datetime.timedelta(days=1)

    missing_dates = find_missing_dates(date_list)
    handle_missing_dates(missing_dates)

def find_missing_dates(date_list):
    missing_dates = []
    current_date = date_list[0]

    for date in date_list:
        if date != current_date:
            while current_date < date:
                missing_dates.append(current_date)
                current_date += datetime.timedelta(days=1)
        current_date += datetime.timedelta(days=1)

    return missing_dates

def handle_missing_dates(missing_dates):
    # 处理缺少的日期逻辑
    pass

start_date = datetime.date(2022, 1, 1)
end_date = datetime.date(2022, 12, 31)
allocate_dates(start_date, end_date)