如何为该JSON响应生成POJO文件以进行自动反序列化？

// 导入Jackson库的相关类
import com.fasterxml.jackson.databind.ObjectMapper;

// 定义POJO类
public class MyResponse {
    private String name;
    private int age;

    // 提供getter和setter方法

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

// 在代码中使用Jackson库进行JSON到POJO的转换
public class Main {
    public static void main(String[] args) {
        String jsonResponse = "{\"name\":\"John\", \"age\":30}";

        try {
            // 创建ObjectMapper对象
            ObjectMapper objectMapper = new ObjectMapper();

            // 将JSON响应转换为POJO对象
            MyResponse myResponse = objectMapper.readValue(jsonResponse, MyResponse.class);

            // 访问POJO对象的属性
            System.out.println("Name: " + myResponse.getName());
            System.out.println("Age: " + myResponse.getAge());
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}